練習問題/解答例/Caesar暗号解読/Python の変更点

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#author("2026-06-23T10:25:54+09:00;2023-02-23T23:33:35+09:00","default:vip","vip")
#author("2026-06-23T11:19:31+09:00;2023-02-23T23:33:35+09:00","default:vip","vip")
[[練習問題]]
 a = 'abcdefghijklmnopqrstuvwxyz .,-'
 s = 'qdq-gi.q-a ziatmxxitmdqibtqi-ustbi ri.qmoqrcxi.qbubu zir -ibtqi-qp-qaai ripmymsqkir -ibtqi-qy dmxi ri.cnxuoi rruoumxakir -ibtqiqzmobyqzbki-q.qmxi -imyqzpyqzbi rixmeaki -puzmzoqai -i-qscxmbu zaimzpir -i btq-iymbbq-a;iz -iatmxximzgi.q-a zinqiuzimzgiemgipuao-uyuzmbqpimsmuzabir -ia. za -uzsiacotimi.qbubu zj'
 for i in range(len(a)):
     candidate = ''.join(';' if e==';' else a[(a.find(e) + i) % len(a)] for e in s)
     if 'person' in candidate:
         print(candidate)
         break

#初心者用

 # coding:utf-8
 table_str = "abcdefghijklmnopqrstuvwxyz .,-abcdefghijklmnopqrstuvwxyz .,-"
 encrypted = "qdq-gi.q-a ziatmxxitmdqibtqi-ustbi ri.qmoqrcxi.qbubu zir -ibtqi-qp-qaai ripmymsqkir -ibtqi-qy dmxi ri.cnxuoi rruoumxakir -ibtqiqzmobyqzbki-q.qmxi -imyqzpyqzbi rixmeaki -puzmzoqai -i-qscxmbu zaimzpir -i btq-iymbbq-a;iz -iatmxximzgi.q-a zinqiuzimzgiemgipuao-uyuzmbqpimsmuzabir -ia. za -uzsiacotimi.qbubu zj"
 
 A = "abcdefghijklmnopqrstuvwxyz .,-abcdefghijklmnopqrstuvwxyz .,-"
 B = "qdq-gi.q-a ziatmxxitmdqibtqi-ustbi ri.qmoqrcxi.qbubu zir -ibtqi-qp-qaai ripmymsqkir -ibtqi-qy dmxi ri.cnxuoi rruoumxakir -ibtqiqzmobyqzbki-q.qmxi -imyqzpyqzbi rixmeaki -puzmzoqai -i-qscxmbu zaimzpir -i btq-iymbbq-a;iz -iatmxximzgi.q-a zinqiuzimzgiemgipuao-uyuzmbqpimsmuzabir -ia. za -uzsiacotimi.qbubu zj"
 G = []
 table = []
 for c in table_str:
     table.append(c)
 # table は ['a', 'b', ...] になった
 
 for i in range(len(A)):
	 G.append(A[i:i + 1])
 
 L = ["p", "e", "r", "s", "o", "n"]
 for k in range(1,len(A)/2):
	 N = ""
	 for q in range(len(L)):
		 w = G.index(L[q])
		 N += G[w + k]
	 if N in B:
		 C = []
		 H = ""
		 for t in range(len(B)):
			 C.append(B[t:t + 1])
		 for y in range(len(B)):
			 if C[y] == ";":
				 H += ";"
			 else:
				 v = G.index(C[y])
				 H += G[v - k]
		 print H
 needle_chars = ["p", "e", "r", "s", "o", "n"]
 for stride in range(1, len(table)//2):
     # "person"をstride幅で暗号化
     needle_enc = ""
     for c1 in needle_chars:
         idx = table.index(c1)
         needle_enc += table[idx + stride]
         
     # 問題の暗号文が暗号化済"person"を含んでいれば勝ち
     if needle_enc in encrypted:
         decrypted = ""
         for c2 in encrypted:
             if c2 == ";":
                 decrypted += ";"
             else:
                 idx2 = table.index(c2)
                 decrypted += table[idx2 - stride] # pythonはリスト番号がボチボチ負でもOK
         print(decrypted)
         break